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Chemistry Ncert Solution Class 12 Chapter 11

CBSE NCERT Solutions For Class 12 Chemistry Chapter 11: If you are looking for the NCERT Solutions for Class 12 Chemistry Chapter 11, you have come to the right place. Alcohols and Phenols find wide applications in industry as well as in day-to-day life. For instance, have you ever noticed that the ordinary spirit used for polishing the wooden furniture is chiefly a compound containing hydroxyl group, ethanol? The sugar we eat, the cotton used for fabrics, the paper we use for writing, are all made up of compounds containing -OH groups.

This NCERT Class 12 Chemistry Chapter 11 explains that alcohol contains one or more hydroxyl (OH) group(s) directly attached to a carbon atom(s), of an aliphatic system (CG3OH). While a phenol contains -OH group(s) directly attached to a carbon atom(s) of an aromatic system (C6H5OH). Solving the Solutions for NCERT Class 12 Chemistry Chapter 11 will further clarify any confusion you might have on these topics. We get you the detailed NCERT Solutions for Class 12 Chemistry Chapter 11.

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NCERT Solutions For Class 12 Chemistry Chapter 11: Alcohols, Phenols & Ethers

The topics and sub-topics included in NCERT Class 12 Chemistry Chapter 11 Alcohols, Phenols, and Ethers are as below:

11.1 Classification
11.2 Nomenclature
11.3 Structures of Functional Groups
11.4 Alcohols and Phenols
11.5 Some Commercially Important Alcohols
11.6 Ethers

Now let us go through the brief description of Class 12 Chemistry Chapter 11.

Chapter Description of CBSE Class 12 Chemistry Chapter 11 – Alcohols, Phenols & Ethers

The name alcohol comes from the name of the alkane from which the alcohol is derived, by substituting 'e' of alkane with the suffix 'ol'. The positions of substituents are indicated by numerals. For this, the longest carbon chain is numbered starting at the end nearest to the hydroxyl group. The positions of the -OH group and other substituents are indicated by using the numbers of carbon atoms to which these are attached. For naming polyhydric alcohols, the 'e' of alkane is retained and the ending 'ol' is added.

In CBSE NCERT Class 12 Chemistry Chapter 11, students will further know that the simplest hydroxy derivative of benzene is phenol. It is a common name and also an accepted IUPAC name. A structure of phenol involves a benzene ring, in its substituted compounds the terms ortho (1,2- disubstituted, meta (1,3- disubstituted) and para (1,4- disubstituted) are often used in the common names. Download and solve the Solutions for NCERT Class 12 Chemistry Chapter 11 PDF given below. Get a better idea of the related concepts.

NCERT Solutions for Class 12 Chemistry Chapter 11 Free PDF

Academic experts at Embibe prepared these NCERT Solutions for Class 12 Chemistry Chapter 11 PDFs as per the CBSE guidelines. You can use these solutions as reference material as you try to solve the exercise questions on your own. Here, we have provided you with some questions-answers just to highlight our approach in the PDF file. If you are satisfied, then you can go ahead and download the complete NCERT Solution PDF file.

Q: Explain why propanol has a higher boiling point than of hydrocarbon, butane?
A: Propanol undergoes intermolecular H-bonding because of the presence of a −OH group. On the other hand, butane does not form H-bonding. Butane is bonded by Van der Waal's forces which is weaker than H-bond. Therefore, extra energy is required to break hydrogen bonds. For this reason, propanol's boiling point is higher than hydrocarbon butane.

Q: Alcohols are comparatively more soluble in water than hydrocarbons of comparable molecular masses. Explain this fact.
A: Alcohols form hydrogen bonds with water due to the presence of −OH group since H has +δ and O has lone pair. However, hydrocarbons cannot form H-bonds with water. Therefore, alcohols are more soluble in water than hydrocarbons of comparable molecular masses.

Q: While separating a mixture of ortho and para nitrophenols by steam distillation, name the isomer which will be steam volatile. Give reason.
A: Intramolecular H-bonding is present in o-nitrophenol while in p-nitrophenol, the molecules are strongly associated due to the presence of intermolecular bonding. Hence, due to intramolecular H-bond, o-nitrophenol is steam volatile.

DOWNLOAD CBSE CLASS 12 CHEMISTRY CHAPTER 11 SOLUTIONS PDF HERE

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This CBSE Class 12 Chemistry Chapter 11 Solutions for Alcohols, Phenols, and Ethers will help you clear your doubts. To boost up your preparation, Embibe provides you with the freeClass 12 Chemistry Chapter 11 Mock Test.

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FAQs Related to NCERT Solutions for Class 12 Chemistry Chapter 11 PDF

Q. Where can I solve Phenol practice questions?
A.  You can solve CBSE Class 12 Chemistry Chapter 11 Alcohol and Ethers questions for free on Embibe.

Q. What are the exercises in NCERT Solutions for Class 12 Chemistry Chapter 11 PDF Download?
A. Check the list of NCERT Solutions for Class 12 Chemistry Part 2 Chapter 11:
Ex. 11.1: Classification
Ex. 11.2: Nomenclature
Ex. 11.3: Structures of Functional Groups
Ex. 11.4: Alcohols and Phenols
Ex. 11.5: Some Commercially Important Alcohols
Ex. 11.6: Ethers

Q. Where can I solve Alcohol and Ethers practice questions?
A.  You can solve CBSE Class 12 Chemistry Chapter 11 Alcohol and Ethers questions for free on Embibe.

Q. What are the main commercial uses of alcohol?
A. Uses of Alcohols:
Alcoholic Drinks.
Industrial methylated spirits.
Use of ethanol as a fuel.
Ethanol as a solvent.
Methanol as a fuel.
Methanol as an industrial feedstock

Q. How Alcohol, Phenol, and Ether is formed?
A. Alcohol is formed when a saturated carbon atom is bonded to a hydroxyl (-OH) group.
Phenol is formed when a hydrogen atom in a benzene molecule is replaced by the -OH group.
Ether is formed when an oxygen atom is connected to two alkyl or aryl groups.

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Chemistry Ncert Solution Class 12 Chapter 11

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